The calculations of relative levels start with finding the difference
between absolute levels.
Maximum permitted relative levels in dBm0 are
obtained from the appropriate parameter.
Assume that the normal level at the TLP is -10 dBm. If the
level of the second harmonic is -38 dBm, what is the
relative level of the second harmonic?
The difference in decibels between the TLP normal level (-
10 dBm) and the second harmonic level (-38 dBm) is 28 dB.
Since -10 dBm is equivalent to 0 dBm0, the relative
harmonic level is -28 dBm0.
If the parameter requirement of harmonic level is at least
-35 dBm0, is the parameter satisfied?
No, because -28 dBm0 is a higher relative level than -35
In other words, the harmonic level is 7 dB higher
than can be tolerated under the specified parameter.
10 dB below the normal signal level at TLP of the circuit, at a frequency of
700 Hz. Then connect the oscillator to the sending end of the line in place
of the normal line signal.